Count distinct values in an ordered list

Question

Given a nondecreasing integer sequence, report how many different values it contains.

```python
def solve(raw: str) -> str: ...
```

## Requirements

- The input is one line of space-separated integers in nondecreasing order.
- Equal values are therefore adjacent, and the sequence may contain negative values.
- Return the number of distinct values as a decimal string.
- You do not need to print or return the compacted sequence itself.
- `run_case(case: dict)` forwards `case["stdin"]` to `solve`.
- Do not append a trailing newline to the returned string; return the value exactly once.