Zero rows and columns around each zero

Question

Given a matrix, set every cell in a row or column that contains a zero to zero, deciding which rows and columns to clear from the original values rather than from the partially rewritten matrix.

```python
def solve(raw: str) -> str: ...
```

## Requirements

- Line 1 is `rows cols`. The next `rows` lines each hold `cols` integers.
- For every cell that is `0` in the original matrix, its entire row and entire column become `0`.
- Decide all affected rows and columns before writing any zeros, so zeros created by the update must not widen the cleared area.
- Return the matrix with rows in their original order, values separated by single spaces and rows separated by newlines, with no extra text.
- A matrix with no zeros is returned unchanged.
- `run_case(case: dict)` forwards `case["stdin"]` to `solve`.
- Do not append a trailing newline to the returned string; return the value exactly once.